一元二次方程2x²-3x+1=0化为（x+a）²=b的形式
问题描述：
一元二次方程2x²-3x+1=0化为（x+a）²=b的形式
答
2x²-3x+1=0
x²-3/2*x+1/2=0
x²-2*3/4*x+(3/4)²-(3/4)²+1/2=0
x²-3/2*x+9/16=-1/2+9/16
(x-3/4)²=1/16
答
（√2 x-3/4√2）^2=（√2/4）^2
答
（x-3/4)的平方=1/16
答
2(x-3/4)²=1/8;
(x-3/4)²=1/16;
答
因式分解就是(2X-1)(X-1)
另一个就是2（X-3/4）-7/2
答
(x-3/4)²=1/16
答
2x^2-3x+1=0
2(x-1.5)^2=3.5
(x-1.5)^2=1.75
答
2x²-3x+1=0
x²-3/2*x+1/2=0
x²-3/2*x=-1/2
x²-3/2*x+9/16=-1/2+9/16
(x-3/4)²=1/16
答
2x²-3x+1=0
x²-3/2x+1/2=0
x²-3/2x+(3/4)²=(3/4)²-1/2
(x-3/4)²=1/16