设函数f(x)=loga x (a>0,a不等于1),若f(x1)+f(x2)=1,则 f(x1^2)+f(x2^2)=
问题描述：
设函数f(x)=loga x (a>0,a不等于1),若f(x1)+f(x2)=1,则 f(x1^2)+f(x2^2)=
答
f(x1^2)+f(x2^2)=loga x1^2 +loga x2^2 =2loga x1 + 2loga x2 =2(loga x1 + loga x2) =2(f(x1)+f(x2)) =2 ---------------------------------------用...