设ab是有理数,且ab满足等式a的平方+2b+根号2b=17-4根号2,求a+b的值
问题描述:
设ab是有理数,且ab满足等式a的平方+2b+根号2b=17-4根号2,求a+b的值
答
5-4=1或-5-4=-9
答
ab是有理数,且ab满足等式a的平方+2b+根号2b=17-4根号2
a的平方+2b=17
b=-4
解得:a=5,b=-4或a=-5,b=-4
所以a+b的值5-4=1或-5-4=-9