设ab是有理数,且ab满足等式a的平方+2b+根号2b=17-4根号2,求a+b的值

问题描述:

设ab是有理数,且ab满足等式a的平方+2b+根号2b=17-4根号2,求a+b的值

5-4=1或-5-4=-9

ab是有理数,且ab满足等式a的平方+2b+根号2b=17-4根号2
a的平方+2b=17
b=-4
解得:a=5,b=-4或a=-5,b=-4
所以a+b的值5-4=1或-5-4=-9