设三阶矩阵A(1,0,0,0,4,0,0 0 2),矩阵B满足AB=A+B,求矩阵B.

问题描述:

设三阶矩阵A(1,0,0,0,4,0,0 0 2),矩阵B满足AB=A+B,求矩阵B.

AB=A+B,所以:(A-E)B=A,E为单位矩阵
(A-E)=(0,0,0,0,3,0,0,0,1)
逆矩阵不存在,本题有错误