已知函数fx=2sin(2x-π/6)求函数fx在区间[-π/12,π/2]上的值域
问题描述:
已知函数fx=2sin(2x-π/6)求函数fx在区间[-π/12,π/2]上的值域
答
x∈[-π/12,π/2]
2x∈[-π/6,π]
2x-π/6∈[-π/3,5π/6]
sin(2x-π/6)∈[-√3/2,1]
2sin(2x-π/6)∈[-√3,2]
值域是[-√3,2]