化简sin8°+cos8°\sin8°-cos8°
问题描述：
化简sin8°+cos8°\sin8°-cos8°
答
(sin8°+cos8°)/(sin8°-cos8°)
=(sin8°+cos8°)²/[(sin8°-cos8°)(sin8°+cos8°)]
=[1+sin16°]/[-(cos²8°-sin²8°)]
=-(1+sin16°)/cos16°