1:(x∧2减4x加1)/(3x∧2减7x加3)≤1 ,求x .

问题描述:

1:(x∧2减4x加1)/(3x∧2减7x加3)≤1 ,求x .
2:若ax∧2+5x+c>0的解集为{x|1/3<x<1/2}则a? c?

(x^2-4x+1)/(3x^2-7x+3)《1 (移项,化简)
(2x^2-3x+2)/(3x^2-7x+3)》0
(2x^2-3x+2)恒大于零,所以,
3x^2-7x+3>0
x>(7+√13)/6或x