x⁴+y⁴+z⁴-2x²y²-2x²z²+2y²z²
问题描述:
x⁴+y⁴+z⁴-2x²y²-2x²z²+2y²z²
分解因式
答
=x⁴-2x²y²+y⁴-2x²z²+2y²z²+z⁴=(x²-y²)²-2(x²-y²)z²+z⁴=(x²-y²-z²)²
x⁴+y⁴+z⁴-2x²y²-2x²z²+2y²z²
分解因式
=x⁴-2x²y²+y⁴-2x²z²+2y²z²+z⁴=(x²-y²)²-2(x²-y²)z²+z⁴=(x²-y²-z²)²