求由直线X=0,X=3,Y=0和抛物线Y=3X^2所围成图形的面积.我要详解
问题描述:
求由直线X=0,X=3,Y=0和抛物线Y=3X^2所围成图形的面积.我要详解
答
面积=∫(0,3)3x²dx
=x³|(0,3)
=3³-0³
=27-0
=27