求由直线X=0,X=3,Y=0和抛物线Y=3X^2所围成图形的面积.我要详解

问题描述:

求由直线X=0,X=3,Y=0和抛物线Y=3X^2所围成图形的面积.我要详解

面积=∫(0,3)3x²dx
=x³|(0,3)
=3³-0³
=27-0
=27