f(x)=(x^2-1)^1/2
问题描述:
f(x)=(x^2-1)^1/2
答
f'(x)=1/2(x^2-1)^(1/2-1)*(x^2-1)'=1/2(x^2-1)^(-1/2)*2x=x(x^2-1)^(-1/2)
f(x)=(x^2-1)^1/2
f'(x)=1/2(x^2-1)^(1/2-1)*(x^2-1)'=1/2(x^2-1)^(-1/2)*2x=x(x^2-1)^(-1/2)