sin(2A+B)/sinA-cos(A+B)=2,求sin^2(B)+2cos(2A)
问题描述:
sin(2A+B)/sinA-cos(A+B)=2,求sin^2(B)+2cos(2A)
答
sin(2A+B)=sin(a+a+b)=sina*cos(a+b)+cosa*sin(a+b)
所以sin(2A+B)/sinA-cos(A+B)=cosa*sin(a+b)/sina=2