求不定积分∫(sinx/2)(cosx/2) dx.
问题描述:
求不定积分∫(sinx/2)(cosx/2) dx.
答
∫(sinx/2)(cosx/2) dx
=(1/2)∫sinxdx
=-(1/2)cosx
答
∫(sinx/2)(cosx/2) dx
=∫(1/2)sinxdx
=-(1/2)*cosx+C