log底为2的sinπ/12加log底为2的 cosπ/12
问题描述：
log底为2的sinπ/12加log底为2的 cosπ/12
快
答
解析：log（2,sinπ/12)+log(2,cosπ/12)
=log(2,sinπ/12*cosπ/12)
=log[2,sinπ/6/2]
=log(2,1/4)
=-2