5的1-(log0.2为底3为真数)次幂=?(log4为底3为真数)*(log9为底2为真数)-(log1/2为底4次根号下32=
问题描述:
5的1-(log0.2为底3为真数)次幂=?(log4为底3为真数)*(log9为底2为真数)-(log1/2为底4次根号下32=
答
=5^1÷5^log0.2(3)=5÷0.2^-log0.2(3)=5÷0.2^log0.2(3^-1)=5÷0.2^log0.2(1/3)=5÷1/3=15换底公式=(lg3/lg4)(lg2/lg9)-lg32^(1/4)/lg(1/2)=(lg3/2lg2)(lg2/2lg3)-lg2^(5/4)/(-lg2)=(1/2*1/2)(lg3/lg2)(lg2/lg3)+(5/...