函数f(x)=cos^2(x-π/12)+sin^2(x+π/12)-1是周期为什么的奇还是偶函数
问题描述：
函数f(x)=cos^2(x-π/12)+sin^2(x+π/12)-1是周期为什么的奇还是偶函数
答
cos^2(x-π/12)=[1+cos(2x-π/6)]/2sin^2(x+π/12)=[1-cos(2x+π/6)]/2所以f(x)=[cos(2x-π/6)-cos(2x+π/6)]/2=(cos2xcosπ/6+sin2xsinπ/6-cos2xcosπ/6+sin2xsinπ/6)/2=sin2xsinπ/6所以T=2π/2=πf(x)=(sin2x)/...