若16(x-y)2+40(x-y)+25=0,则x与y的关系式为_.

问题描述:

若16(x-y)2+40(x-y)+25=0,则x与y的关系式为______.

方程16(x-y)2+40(x-y)+25=0,
变形得:[4(x-y)+5]2=0,
开方得:4(x-y)+5=0,
整理得:4x-4y+5=0.
故答案为:4x-4y+5=0