已知sin(x+π/12),x∈(π/2,π),求sin2x,cos2x

问题描述:

已知sin(x+π/12),x∈(π/2,π),求sin2x,cos2x
sin(x+π/12)=3/5

sin(x+π/12)=3/5,cos(x+π/12)=-4/5sin2(x+π/12)=2sin(x+π/12)cos(x+π/12)=-24/25sin2(x+π/12)=sin(2x+π/6)=√3/2sin2x+1/2cos2x=-24/25cos2(x+π/12)=√3/2cos2x-1/2sin2x=7/25sin2x=cos2x=接下来...