6/(x+1)=(x+5)/[x(x+1)] (3-x)/(x-4)+1/(4-x)=1 2/(1+x)-3/(1-x)=6/(x*x-1) (2x-3)/(x-1)=(2x-4)/(2x+3)
问题描述:
6/(x+1)=(x+5)/[x(x+1)] (3-x)/(x-4)+1/(4-x)=1 2/(1+x)-3/(1-x)=6/(x*x-1) (2x-3)/(x-1)=(2x-4)/(2x+3)
答
6/(x+1)=(x+5)/[x(x+1)]6x=(x+5) (两边同乘x(x+1))5x=5 (合并同类项)x=1(3-x)/(x-4)+1/(4-x)=1 (3-x)-1=(x-4) (两边同乘(x-4))2x=6 (合并同类项)x=3 2/(1+x)-3/(1-x)=6/(x²-1)2/(1+x)-3/(1-x)=6/[(x-1)(1+x)]...