(2x-3)(3x-2)-6(x-1)(x+1)其中x=13分之1

问题描述:

(2x-3)(3x-2)-6(x-1)(x+1)其中x=13分之1

(2x-3)(3x-2)-6(x-1)(x+1)
=6x^ - 13x +6 - 6(x^-1)
=6x^ - 13x +6 - 6x^ + 6
= - 13x +12
代入 x = 1/13
= -13× 1/13 + 12
= -1 + 12
= 11