3(x-1)-7(x+5)=30(x+1)和(y+2)/3-(4y-1)/3=2-(2y+5)/6

问题描述:

3(x-1)-7(x+5)=30(x+1)和(y+2)/3-(4y-1)/3=2-(2y+5)/6

3(x-1)-7(x+5)=30(x+1) 3x-3-7x-35=30x+30 30x+7x-3x=-3-35-30 34x=-68 x=-2 (y+2)/3-(4y-1)/3=2-(2y+5)/6 2(y+2)-2(4y-1)=12-(2y+5) 2y+4-8y+2=12-2y-5 2y+2y-8y=12-5-4-2 -4y=1 y=-1/4 3、设有x个房间.依题意:5x+2=6x-8 ∴x=10 ∴5x+2=52 答:有52个住校生,10个房间.