一道不定积分题sin(t^1/2) / t^1/2 dt怎么求啊?
问题描述:
一道不定积分题sin(t^1/2) / t^1/2 dt怎么求啊?
sin(t^1/2) / t^1/2 dt怎么求啊?
答
∫ sin(t^1/2) / t^1/2 dt
=∫ sin(t^1/2) * [t^(-1/2) dt]
= 2 ∫ sin(t^1/2) * dt^(1/2)
= -2 cos(t^1/2) + C