已知x二次方减5X-2013=0,求X-2分之(X-2)2次方-(X-1)二次方+1的值

问题描述:

已知x二次方减5X-2013=0,求X-2分之(X-2)2次方-(X-1)二次方+1的值

答:
x^2-5x-2013=0
[ (x-2)^2 -(x-1)^2+1]/(x-2)
=[(x-2+x-1)*(x-2-x+1)+1 ] /(x-2)
=(-2x+3+1)/(x-2)
=(-2x+4) /(x-2)
=-2