1998×(1/11−1/2009)+11×(1/1998−1/2009)−2009×(1/11+1/1998)+3=_.

问题描述:

1998×(

1
11
1
2009
)+11×(
1
1998
1
2009
)−2009×(
1
11
+
1
1998
)+3=______.

1998×(

1
11
1
2009
)+11×(
1
1998
1
2009
)−2009×(
1
11
+
1
1998
)+3,
=3-(2009-1998)×
1
11
-(1998+11)×
1
2009
-(2009-11)×
1
1998

=3-11×
1
11
-2009×
1
2009
-1998×
1
1998

=3-1-1-1,
=0.
故答案为:0.