先化简:(xy-2y)(xy+2y)-(x-y)2-x2y2,并求当x=1/2、y=2时的代数式的值.
问题描述:
先化简:(xy-2y)(xy+2y)-(x-y)2-x2y2,并求当x=
、y=2时的代数式的值. 1 2
答
原式=x2y2-4y2-(x2-2xy+y2)-x2y2
=x2y2-4y2-x2+2xy-y2-x2y2
=-5y2-x2+2xy,
当x=
,y=2时,原式=-20-1 2
+2=-181 4
.1 4