化简:(x+y)+(2x+1/1×2y)+(3x+1/2×3y)+…+(9x+1/8×9y),并求当x=2,y=9时式子的值.
问题描述:
化简:(x+y)+(2x+
y)+(3x+1 1×2
y)+…+(9x+1 2×3
y),并求当x=2,y=9时式子的值. 1 8×9
答
原式=(x+2x+3x+…+9x)+(1+
+1 1×2
+…+1 2×3
)y1 8×9
=45x+(1+1-
+1 2
-1 2
+1 3
-1 3
+…+1 4
-1 8
)y1 9
=45x+
y,17 9
当x=2,y=9时,
原式=45×2+
×917 9
=107.