已知方程2x+2y+3z=6且x+3y+5z=10,求2z-x+y的值
问题描述:
已知方程2x+2y+3z=6且x+3y+5z=10,求2z-x+y的值
答
(x+3y+5z)-(2x+2y+3z)
=-x+y+2z
=2z-x+y
=10-6=4