4(2x^2-x+1)(x^2-2x+3)-(3x^2-3x+4)^2 换元法因式分解

问题描述:

4(2x^2-x+1)(x^2-2x+3)-(3x^2-3x+4)^2 换元法因式分解
4(2x^2-x+1)(x^2-2x+3)-(3x^2-3x+4)^2
换元法因式分解

令a=2x²-x+1b=x²-2x+3则3x²-3x+4=a+b所以原式=4ab-(a+b)²=4ab-a²-2ab-b²=-(a²-2ab+b²)=-(a-b)²=-(2x²-x+1-x²+2x-3)²=-(x²+x-2)²=-(x-1)...请采纳哦~
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