有几道因式分解不会,16（6x-1)(2x-1)(3x+1)(x-1)+25(6x-1)(2x-1)(3x-1)(x-1)+x的平方（6x-1)(4x-1)(3x-1)(x-1)+9x的四次方(2x-3y)的三次方+(3x-2y)的三次方-125(x-y)的三次方x的四次方+x的三次方-4x的平方+x+14(2x^2-x+1)(x^2-2x+3)-(3x^2-3x+4)^2
问题描述：
有几道因式分解不会,
16（6x-1)(2x-1)(3x+1)(x-1)+25
(6x-1)(2x-1)(3x-1)(x-1)+x的平方
（6x-1)(4x-1)(3x-1)(x-1)+9x的四次方
(2x-3y)的三次方+(3x-2y)的三次方-125(x-y)的三次方
x的四次方+x的三次方-4x的平方+x+1
4(2x^2-x+1)(x^2-2x+3)-(3x^2-3x+4)^2
答
(6x-1)(2x-1)(3x-1)(x-1) + x²
= [(6x-1)(x-1)][(2x-1)(3x-1)] + x²
= (6x²-7x+1)(6x²-5x+1) + x²
= (6x²-6x+1 - x)(6x²-6x+1 + x) + x²
= (6x²-6x+1)² - x² + x²
= (6x² - 6x + 1)²
答
16（6x-1)(2x-1)(3x+1)(x-1)+25=16[（6x-1)(2x-1)][(3x+1)(x-1)]+25=16(12x²-8x+1)(3x²-2x-1)+25=4(12x²-8x+1)(12x²-8x-4)+25设12x²-8x=a原式=4(a+1)(a-4)+25=4(a²-3a-4)+25=4a²...