如图,CD是RT△ABC斜边上的高,E为AC的中点,ED交CB的延长线于F,求证BD*CF=CD*DF
问题描述:
如图,CD是RT△ABC斜边上的高,E为AC的中点,ED交CB的延长线于F,求证BD*CF=CD*DF
答
because in RT△ACD,EA=EC=ED,so EC=ED so ECD=EDCbecause CDB=90 so DBC+DCB=90 because ECD+DCB=90so ECD=DBC=EDCso CDF=DBCso △FBD相似于△FDCso BD/CD=DF/CFso BD*CF=CD*DF