已知函数f(x+2)=log2(-x),x=0,则f(-2)+f(log2^12)=
问题描述:
已知函数f(x+2)=log2(-x),x=0,则f(-2)+f(log2^12)=
答
23/12有木有具体的啊f(-2)+f(log2^12)=f(-4+2)+f(log(2)12)=log2(4)+(1/2)^(log(2)12)=2+2^(log(2)12*(-1))=2+12^(-1)=25/12