|x-y+5|+(3x+y-1)的平方=0怎样解..?

问题描述:

|x-y+5|+(3x+y-1)的平方=0怎样解..?

|x-y+5|>=0 (3x+y-1)^2>=0
|x-y+5|+(3x+y-1)^2>=0
|x-y+5|=0 (3x+y-1)^2=0
x-y+5=0 3x+y-1=0
x=-1 y=4