(x^-3x+2/x^-5x+6)^2÷(x-1/x^2-2x-3)^2
问题描述:
(x^-3x+2/x^-5x+6)^2÷(x-1/x^2-2x-3)^2
答
(x^-3x+2/x^-5x+6)^2÷(x-1/x^2-2x-3)^2
=[(x-1)(x-2)/(x-2)(x-3)]^2÷[(x-1)/(x-3)(x+1)]^2
=(x-1)^2/(x-3)^2*(x-3)^2(x+1)^2/(x-1)^2
=(x+1)^2