(x²-2x﹚²+2x²-4x+1怎么因式分解

问题描述:

(x²-2x﹚²+2x²-4x+1怎么因式分解

(x²-2x﹚²+2x²-4x+1
=[ x(x-2)]的平方+2[x(x-2)]+1
=([x(x-2)]+1)的平方
=(x²-2x+1)²
=(x-1)的四次方