6x(x-2)-(x-2)(3x-1)=3x^2-8怎么计算

问题描述:

6x(x-2)-(x-2)(3x-1)=3x^2-8怎么计算

6x(x-2)-(x-2)(3x-1)=3x^2-8
6x^2-12x-(3x^2-7x+2)=3x^2-8
6x^2-12x-3x^2+7x-2=3x^2-8
-5x-2=-8
5x=6
x=6/5