数列{an}的前n项和为Sn,Sn=1-2/3an,则an=_.

问题描述:

数列{an}的前n项和为Sn,Sn=1-

2
3
an,则an=______.

∵数列{an}的前n项和为Sn,Sn=1-23an,∴a1=s1=1-23a1,解得 a1=35.且n≥2时,an=Sn-Sn-1=(1-23an)-(1-23an-1)=23an-1-23an,化简可得 anan−1=25.故数列{an}是首项为35,公比为25的等比数列,故 an=35×...