(x+√x²;+2008)(y+√y²;+2008)=2008,求x²;-3xy-²;-6x-6y+58的值
问题描述：
(x+√x²;+2008)(y+√y²;+2008)=2008,求x²;-3xy-²;-6x-6y+58的值
答
x+√(x²+2008)=2008/(√(x²+2008)-x)y+√(y²+2008)=2008/(√(y²+2008)-y)[2008/(√(x²+2008)-x)]*[y+√(y²+2008)]=2008[2008/(√(y²+2008)-y)]*[x+√(x²+2008)]=2008√(x&s...