用适当的方法解下列方程(1)x^2+6x=4.(2)2(x-3)^2=3(x-3.(3)2x^2-7x-3=0.(4)(2x-5)^2-(x+4)^2=0
问题描述：
用适当的方法解下列方程(1)x^2+6x=4.(2)2(x-3)^2=3(x-3.(3)2x^2-7x-3=0.(4)(2x-5)^2-(x+4)^2=0
答
解x²+6x=4x²+6x+9=13∴(x+3)²=13∴x+3=±√13∴x=-3±√132(x-3)²=3(x-3)2(x-3)²-3(x-3)=0(x-3)(2x-6-3)=0∴x=3或x=9/22x²-7x-3=0△=b²-4ac=49+24=73∴x=(7+√73)/4或x=(7-√73)...