已知a/sinA=2,则a+b+c/sinA+sinB+sinC=_.
问题描述:
已知
=2,则a sinA
=______. a+b+c sinA+sinB+sinC
答
由正弦定理可得
=a sinA
=b sinB
c sinC
∴
=a+b+c sinA+sinB+sinC
a sinA
∵
=2a sinA
∴
=2a+b+c sinA+sinB+sinC
故答案为:2