已知a/sinA=2,则a+b+c/sinA+sinB+sinC=_.

问题描述:

已知

a
sinA
=2,则
a+b+c
sinA+sinB+sinC
=______.

由正弦定理可得

a
sinA
=
b
sinB
=
c
sinC

a+b+c
sinA+sinB+sinC
=
a
sinA

a
sinA
=2

a+b+c
sinA+sinB+sinC
=2
故答案为:2