如图,△ABC和△AlBlC1均为正三角形,BC和B1C1的中点均为D.求证:AA1⊥CC1.

问题描述:

如图,△ABC和△AlBlC1均为正三角形,BC和B1C1的中点均为D.求证:AA1⊥CC1

证明:连接AD,延长AA1交DC于O,交C1C于E,
∵∠ADA1=90°-∠A1DC=∠CDC1

AD
DC
=
DA1
DC1
=
3

∴△AA1D∽△CC1D,∠A1AD=∠C1CD,
又∵∠AOD=∠COE,
∴∠ADO=∠CEO=90°,即AA1⊥CC1