sin(π/6+α)=3/5,则cos(α-π/3)=

问题描述:

sin(π/6+α)=3/5,则cos(α-π/3)=
不理解 cos(α-π/3)=cos(π/3-a)=3/5

sin(π/6+a)=sin[π/2-(π/3-a)]=cos(π/3-a)
因sin(π/6+a)=3/5,则:cos(π/3-a)=3/5
则cos(α-π/3)=cos(π/3-a)=3/5