[(1-log6 3)^2+log6 2·log6 18]·log4 6
问题描述：
[(1-log6 3)^2+log6 2·log6 18]·log4 6
倒数第二步怎么来的？
答
=1
=[(log6 6-log6 3)^2+log6 2*log6 18]*log4 6
=[(log6 2)^2+log6 2*(log6 2+log6 9]*log4 6
=[2(log6 2)^2+2log6 2*log6 3]*(1/log6 4)
=log6 2+log6 3
=1