求值：[log6(3)]^2+log6(18)/log2(6)很着急.
问题描述：
求值：[log6(3)]^2+log6(18)/log2(6)很着急.
我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有（乘）变为（加）,而且为什么要将它平方?
[log6(3)]^2+log6(18)/log2(6)
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
答
[log6(3)]^2+log6(18)/log2(6)
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)+[log6(2)]^2
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
第三步少了【log6(2)】^2