化简：sin(x+π/3)-√3cos(2π/3-x)+2sin(x-π/3)=
问题描述：
化简：sin(x+π/3)-√3cos(2π/3-x)+2sin(x-π/3)=
答
展开得到
原式
=sinx*cosπ/3 +cosx *sinπ/3 - √3 *cos2π/3 *cosx -√3 *sin2π/3*sinx +2sinx*cosπ/3 -2cosx *sinπ/3
=sinx* 1/2 +cosx *√3/2 -√3 *(-1/2) *cosx -√3 *√3/2 *sinx +2sinx *1/2 -2cosx *√3/2
=(1/2 -3/2+1)*sinx +(√3/2 +√3/2 -√3)*cosx
=0