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[sin(540-x)/tan(900-x)]*[1/tan(450-x)*tan(810-x)]*[cos(360-x)/sin(-x)]

分类: 作业答案 • 2021-12-28 17:56:06
问题描述：

[sin(540-x)/tan(900-x)]*[1/tan(450-x)*tan(810-x)]*[cos(360-x)/sin(-x)]

答

sin(540-x)cos(360-x) / tan(900-x)tan(450-x)tan(810-x)sin(-x)
= sin(180-x)cos(-x) / tan(180-x)tan(90-x)tan(90-x)sin(-x)
= - sin(x)cos(x)tan(x)tan(x)cos(180-x) / sin(180-x)sin(x)
= cos^2(x)tan^2(x) / sin(x)
= sinx

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