函数f(x)=根号2 sin(2x+π/4)令g(x)=f(x+π/8)-a,若g(x)在x∈[-π/6,π/3]时有两个零点,
问题描述:
函数f(x)=根号2 sin(2x+π/4)令g(x)=f(x+π/8)-a,若g(x)在x∈[-π/6,π/3]时有两个零点,
求a的取值范围
答
函数f(x)=根号2 sin(2x+π/4)g(x)=f(x+π/8)-a=根号2 sin(2(x+π/8)+π/4)-a=根号2sin(2x+π/2)-a=根号2cos(2x)-ax∈[-π/6,π/3] 2x∈[-π/3,2π/3] 根号2cos(2x) ∈[-√2/2,√2] 由图像可知 g(x)在x∈...