2x^2+4xy+2y^2+7x+7y+3

分类: 作业答案 • 2021-12-28 17:16:56

问题描述：

2x^2+4xy+2y^2+7x+7y+3
因式分解

答

2x²+4xy+2y²+7x+7y+3
=2(x²+2xy+y²)+7(x+y)+3
=2(x+y)²+7(x+y)+3
=[2(x+y)+1][(x+y)+3]
=(2x+2y+1)(x+y+3)