sin^4a-cos^4a=sin^2a-cos^2a
问题描述:
sin^4a-cos^4a=sin^2a-cos^2a
答
sin^4a-cos^4a=(sin^2a-cos^2a)(sin^2a+cos^2a)=(sin^2a-cos^2a)*1=sin^2a-cos^2a
sin^4a-cos^4a=sin^2a-cos^2a
sin^4a-cos^4a=(sin^2a-cos^2a)(sin^2a+cos^2a)=(sin^2a-cos^2a)*1=sin^2a-cos^2a