求a=1999时,3a³-2a²+4a-1-(3a³-3a²+3a-2001)的值
问题描述：
求a=1999时,3a³-2a²+4a-1-(3a³-3a²+3a-2001)的值
答
3a³-2a²+4a-1-(3a³-3a²+3a-2001)=3a³-2a²+4a-1-3a³+3a²-3a+2001=a²+a+2000=a(a+1)+2000=1999×2000+2000=2000×(1999+1)=2000×2000=4000000