1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)用找规律的方法计算
问题描述:
1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)用找规律的方法计算
答
思路就是把三个变成同底数:(x-1)(x-2)(x-3).1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)=(x-1)/(x-1)(x-2)(x-3)-2(x-2)/(x-1)(x-2)(x-3)+(x-3)/(x-1)(x-2)(x-3)=(x-1)-2(x-2)+(x-3)/(x-1)(x-2)(x-3)=0/(x-1)(x-2)(x-3)=0