(a+2b)²+______=a²+2ab+4b²

问题描述:

(a+2b)²+______=a²+2ab+4b²
若x²+2x=1,则(x+1)²=

(a+2b)²+_(-2ab)_____=a²+2ab+4b²
(x+1)^2
=x^2+2x+1
∵x^2+2x=1
∴(x+1)^2=1+1=2
若x²+2x=1,则(x+1)²=(2)